ELECTROMAGNETICS
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CHAPTER 1 
P. E. 1.1 
= A(a+) B + 1(,0, 3−) (=5,2, 6−) 6(,2, 3 ) 
A= +B +3 46 + 9= 7 
(bA) B5= − −(5,0, 15 ) (5,2, −6 ) =0(, 2−, 21 ) 
(c) The component of A along ay is Ay = 0 
(dA) B 3= + +(3,0, 9 ) (5,2, −6 ) = (8,2, 3 ) 
A unit vector parallel to this vector is 
( ) 
( ) x y z a a a 
a 
0.9117 0.2279 0.3419 
6 44 9 
,82 , 3 
11 
= ± + + 
++ 
= 
P. E. 1.2 (a) 3 5 p x y z r = a − a + a 
8 R y z r = 3a + a 
(b) The distance vector is 
(0,3,8) (2, 4,6) 2 2 QR R Q x y z r = r −...
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