, ·
DIFFERENTIAL EUQATIONS
Order Methods of Solving STEP 1 STEP 2
is the order of the highest order derivative in the equation.
0 = 2 0 = 3 0= 2 Variable Separable Homogenous D.E. Linear D.E
STEP 3 STEP 4 Solve
Variable Separable =• 𝑥−𝑦
𝑑𝑦
𝑑𝑥
= 𝑥 + 2𝑦
𝑑𝑦 𝑥+𝑦
Degree • =
𝑑𝑦 𝑑𝑦 1+𝑦 2 𝑑𝑥 𝑥
• = 𝑥𝑦 • = 𝑥 𝑥
𝑑𝑥 𝑑𝑥 1+x2
• 2𝑦𝑒 𝑦 𝑑𝑥 + 𝑦 − 2𝑥𝑒 𝑦 𝑑𝑦 = 0, 𝑤ℎ𝑒𝑛 𝑥 = 0, 𝑦 = 1
is the degree (power) of the highest order derivative 𝑑𝑦 𝑥 𝑑𝑦 𝑥+1
• =𝑦 • = 2−𝑦
𝑑𝑥 𝑑𝑥
0 =3 0 = 3
D =2 D=1 -
Linear D.E
𝑑𝑦 2
Find particular solution when y=1, x=0, = −4𝑥𝑦
𝑑𝑥
𝒅𝒚
0 =2 not defined
.
+ 𝑷𝒚 = 𝑸
The degree of the differential equation
𝑑2 𝑦
+ 𝑠𝑖𝑛
𝑑𝑦 Be
+ 2𝑦 = 0 is 𝒅𝒙 P and Q are constants or functions of x only
𝑑𝑥 2 𝑑𝑥
Homogenous D.E. Integrating Factor (I.F)=𝑒 𝑥𝑑𝑃
Particular & General Solution
• A function F(x, y) is said to be homogeneous function
of degree n if F(λx, λy) = λn F(x, y) for any constant λ. Solution: 𝒚 𝑰. 𝑭 = 𝒙𝒅 𝑭𝑰 × 𝑸 + 𝑪
• Particular Solution – No Arbitrary Constants
• General Solution –# Arbitrary Constants = Order of D.E • A function is said to be homogenous, if 𝑑𝑦
• 𝐹𝑖𝑛𝑑 𝐼𝐹: 𝑥 𝑑𝑥 + 2𝑦 = 𝑥 2
𝑦 𝑥
𝐹 𝑥, 𝑦 = 𝑥 𝑛 . 𝑔 𝑜𝑟 𝑦 𝑛 . 𝑔
𝑥 𝑦 𝑑𝑦 𝑦
• 𝐹𝑖𝑛𝑑 𝑔𝑒𝑛𝑒𝑟𝑎𝑙 𝑠𝑜𝑙𝑛: 𝑑𝑥 + 𝑥 = 𝑥2
, -
3)
(an
S y =
-
9 +C
2) =
& @my failyt
-
-
I
I 2u+ 2
Jayade Jydy Jude
- =
=
-
Y
1 2xx + c
=
-
-
=
T
loglyl = Szydy fat , du *I -
-
-
-2-1
+
..
I
=
y e
2y-n +
=
=
-
- -
, ad
=
+
nav v= log() + 2
Fey) Xy
+
+ ~
& log(1 + 2
=
=
N
An -
-
ka) u n+ Vu
=
-
du U
-homogenous .
n M
V+ =
Vu
y =
V + udv udr
do
v
I+V
-
= =
-
an An
DIFFERENTIAL EUQATIONS
Order Methods of Solving STEP 1 STEP 2
is the order of the highest order derivative in the equation.
0 = 2 0 = 3 0= 2 Variable Separable Homogenous D.E. Linear D.E
STEP 3 STEP 4 Solve
Variable Separable =• 𝑥−𝑦
𝑑𝑦
𝑑𝑥
= 𝑥 + 2𝑦
𝑑𝑦 𝑥+𝑦
Degree • =
𝑑𝑦 𝑑𝑦 1+𝑦 2 𝑑𝑥 𝑥
• = 𝑥𝑦 • = 𝑥 𝑥
𝑑𝑥 𝑑𝑥 1+x2
• 2𝑦𝑒 𝑦 𝑑𝑥 + 𝑦 − 2𝑥𝑒 𝑦 𝑑𝑦 = 0, 𝑤ℎ𝑒𝑛 𝑥 = 0, 𝑦 = 1
is the degree (power) of the highest order derivative 𝑑𝑦 𝑥 𝑑𝑦 𝑥+1
• =𝑦 • = 2−𝑦
𝑑𝑥 𝑑𝑥
0 =3 0 = 3
D =2 D=1 -
Linear D.E
𝑑𝑦 2
Find particular solution when y=1, x=0, = −4𝑥𝑦
𝑑𝑥
𝒅𝒚
0 =2 not defined
.
+ 𝑷𝒚 = 𝑸
The degree of the differential equation
𝑑2 𝑦
+ 𝑠𝑖𝑛
𝑑𝑦 Be
+ 2𝑦 = 0 is 𝒅𝒙 P and Q are constants or functions of x only
𝑑𝑥 2 𝑑𝑥
Homogenous D.E. Integrating Factor (I.F)=𝑒 𝑥𝑑𝑃
Particular & General Solution
• A function F(x, y) is said to be homogeneous function
of degree n if F(λx, λy) = λn F(x, y) for any constant λ. Solution: 𝒚 𝑰. 𝑭 = 𝒙𝒅 𝑭𝑰 × 𝑸 + 𝑪
• Particular Solution – No Arbitrary Constants
• General Solution –# Arbitrary Constants = Order of D.E • A function is said to be homogenous, if 𝑑𝑦
• 𝐹𝑖𝑛𝑑 𝐼𝐹: 𝑥 𝑑𝑥 + 2𝑦 = 𝑥 2
𝑦 𝑥
𝐹 𝑥, 𝑦 = 𝑥 𝑛 . 𝑔 𝑜𝑟 𝑦 𝑛 . 𝑔
𝑥 𝑦 𝑑𝑦 𝑦
• 𝐹𝑖𝑛𝑑 𝑔𝑒𝑛𝑒𝑟𝑎𝑙 𝑠𝑜𝑙𝑛: 𝑑𝑥 + 𝑥 = 𝑥2
, -
3)
(an
S y =
-
9 +C
2) =
& @my failyt
-
-
I
I 2u+ 2
Jayade Jydy Jude
- =
=
-
Y
1 2xx + c
=
-
-
=
T
loglyl = Szydy fat , du *I -
-
-
-2-1
+
..
I
=
y e
2y-n +
=
=
-
- -
, ad
=
+
nav v= log() + 2
Fey) Xy
+
+ ~
& log(1 + 2
=
=
N
An -
-
ka) u n+ Vu
=
-
du U
-homogenous .
n M
V+ =
Vu
y =
V + udv udr
do
v
I+V
-
= =
-
an An